What are the names of the first four members of the homologous series of alkenes?

The correct answer is the first four members of the homologous series of alkenes are ethene, propene, butene, and pentene. Alkenes are characterized by having at least one double bond between carbon atoms, which distinguishes them from alkanes, the saturated hydrocarbons.

The series starts with ethene, which has two carbon atoms and the simplest structure of a double bond, followed by propene with three carbon atoms, then butene with four, and finally pentene with five. Each successive member of the homologous series increases by a CH₂ unit, maintaining the same general chemical properties while exhibiting slight variations in their physical properties due to their differing molecular sizes.

The other options represent either various alkenes but starting from incorrect first members or entirely different families of hydrocarbons, such as alkanes, which are not part of the alkene series. Therefore, the progression of the first four members in the alkenes is best represented by ethene, propene, butene, and pentene.